sin29π/6+cos(-29π/3)+tan(-25/4)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/16 06:31:20
sin29π/6+cos(-29π/3)+tan(-25/4)sin29π/6+cos(-29π/3)+tan(-25/4)sin29π/6+cos(-29π/3)+tan(-25/4)sin29π/
sin29π/6+cos(-29π/3)+tan(-25/4)
sin29π/6+cos(-29π/3)+tan(-25/4)
sin29π/6+cos(-29π/3)+tan(-25/4)
sin29π/6+cos(-29π/3)+tan(-25π/4) =sin(24π/6+5π/6)+cos(-30π/3+π/3)+tan(-24π/4-π/4) =sin5π/6+cosπ/3-tanπ/4
sin29π/6+cos(-29π/3)+tan(-25/4)
sin29π/6+cos(-29π/3)+tan(-25π/4)要求是求值
sin29/6π+COS(-29/3π)+tan(-25/4π)答案拜托了各位
cos(-29兀/3)+tan(-25兀/4)+sin29兀/6的化简过程?
求值(1)sin29/6π(2)cos31/4π(3)tan(-1560°)
(3)sin29π/9cos4π/9+sin41π/18cos19π/18
(3)sin29π/9cos4π/9+sin41π/18cos19π/18
求值sin29/6π cos31/4π tan(-1560°)
求值:sin29π|9cos4π|9+sin41π|18cos19π|18哥哥,姐姐们帮帮小弟……
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
请问 sin10度29分和sin29度58分分别等于多少?
正弦29度除以余弦61度 sin29°/cos61°-tan36°*tan54°
Cos[π/7] + Cos[2 π/7] + Cos[3 π/7] + Cos[4 π/7] + Cos[5 π/7] + Cos[6 π/7] + Cos[7π/7]过程思路 不要只有答案哦
sin29等于多少呀
sin29 怎么算啊
cos^3(-π-α)
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)