求 sin y/cos y dy=sin x/cos x dx 两边同时积分的计算过程

求 sin y/cos y dy=sin x/cos x dx 两边同时积分的计算过程 y=x*sin(lnx) 求dy sin(xy)=x+y,求dy x=θ(1-sinθ) y=θcosθ 求dy/dx 求导：x=cos^4*t,y=sin^4*t,求dy/dx 设x=e'sin t,y=e'cos t,求dy/dx. y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示 y=f(sin²x)+f(cos²x),求dy d{cos(x-y)=sin(x-y)(dx-dy)这里dx-dy是什么意思呢? 设y=y(x)由方程cos(x+y)+y=1,求dy/dx我做到-sin(x+y)*(x+y)'+y'=0 y=sin@/2-cos@求值域 求微分 y=sin²x 求dy y=sin(lnx) +1/x,求dy求详解 设sin(x+y)=xy,求dy/dx. 设函数 y=sin×2+2× 求dy xy-sin(πy^2)=0 求dy/dx x=sin(y/x)+e^2 求dy/dx 求通解dy/dx=sin(x-y)