设y=y(x)由y-xe^y=1所确定,求dy/dx

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设y=y(x)由y-xe^y=1所确定,求dy/dx设y=y(x)由y-xe^y=1所确定,求dy/dx设y=y(x)由y-xe^y=1所确定,求dy/dxy-xe^y=1y''-[x''e^y+x(e^

设y=y(x)由y-xe^y=1所确定,求dy/dx
设y=y(x)由y-xe^y=1所确定,求dy/dx

设y=y(x)由y-xe^y=1所确定,求dy/dx
y-xe^y=1
y ' - [x ' e^y + x(e^y)'] = 0
y ' - [ e^y + x y ' e^y ] = 0
(1 - x e^y)y ' = e^y
y ' = e^y /(1 - x e^y)