若|2x+y-1|+(x-2y)²=0,则x²+xy+y²的值为?急如立令

若|2x+y-1|+(x-2y)²=0,则x²+xy+y²的值为?急如立令
若|2x+y-1|+(x-2y)²=0,则x²+xy+y²的值为?
急如立令

若|2x+y-1|+(x-2y)²=0,则x²+xy+y²的值为?急如立令
|2x+y-1|≥0 (x-2y)²≥0
两式相加为0
所以2x+y-1=0且x-2y=0
即x=0.4 y=0.2
所以x²+xy+y²=0.16+0.08+0.04=0.28