已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=
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已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=已知数列{an}满足
已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=
已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=
已知数列{an}满足a1=2,(an+1)=1+an/1-an(n∈N+),则a2012=
a1=2 a2=-3 a3=-1/2 a4=1/3 a5=2
a6=-3…… T=4
a2012=a4=1/3
a1=2
a2=-1
a3=1/2
a4=2
a5=-1
a6=1/2
a7=2
....
a2012=-1
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