a^(n-1)+3a^(n)-6a^(n-2)因式分解..

(3a^n+1+6a^n+2-9a^n)/3a^n-1 (6a^n+2 +3a^n+1 -9a^n)/3a^n-1 计算:(3a^n+2+6a^n+1-9^n)÷3a^n-1 a^n+2+a^n+1-3a^n因式分解 如果n是正整数,[(8a^n+3)-(6a^n+2)-(5a^n+1)]/(-a)^n 分式 计算：a^(2n+1)-6a^(2n)+9a^(2n-1) / a^(n+1)-4a^n+3a^(n-1) 数列a(n)=n (n+1)(n+2)(n+3),求S(n) (3a^n-2)-6a^n+14a^n-1(因式分解） （m-n）^3+4(n-m)（n-2）和（n-1)最为指数 （4a^2n-6a^n+1+2a^n)/2a^n 因式分解 -a^n-(-5a^n-1)-2(a^n-1-3a^n) 化简(a^n+4 - a^3n) / (a^3n+3 - a^n+7) n 是正整数 -(1/a^3) 化简(a^n+4 - a^3n) / (a^3n+3 - a^n+7) n 是正整数 -(1/a^3) 计算:(3a^(n+1)-6a^n+9a^(n-1)/(1/3a^(n-1) 计算(3a^n+1-6a^n+9a^n-1)/(1/3a^n-2) 计算：(6a^n+2-9a^n+1+3a^n-1)÷3a^n-1 (3a^（n+1）+6a^（n+2）-9a^n)/3a^（n-1）是计算 (3a^n+1+6a^n+2-9a^n)/3a^n-1是计算题 （6a^n+2+3a^n+1-9a^n)÷1/2a^n-1 设a,n∈N*证明a^2n-(-a)^n≥(a+1)×a^n