数列{an}首项a1=1,an=2(an-1)+1(n?N*,n大于等于2),令bn=(an)+1,求证{bn}是等比数列,求{an}的通项公式,急用!

数列an中,a1=3,an+1=an/2an+1,则an=? 数列{An}满足a1=1/2,a1+a2+..+an=n方an,求an 数列{an}中,2an*an+1+2an+1-an=0,a1=1,an=? 数列｛an｝中,a1=1/2 3an*an-1+an-an-1=0,通项公式an 数列{an}满足a1=1 an+1=2n+1an/an+2n 在数列an中,a1=1,an=3an-1+2则an= 已知数列{an}中,a1=1/2,an+1+3an=0,an=( ) 设数列{an}中,a1=2,an+1=an+n+1,则通项an=? 数列｛an},a1=1,an+1=2an-n^2+3n,求｛an｝. 已知数列｛an｝,a1=1,an+1=2an/an+2,求a5 数列an集合中,a1=2,an+1=an+(2n+1),求an. 数列an满足a1=2,an+1=4an+9,则an=? 在数列an中,a1=2 an+1=an+3n则an= 数列{an}中,a1=35,an+1-an=2n-1,求an 已知数列an,a1=1 an+1-an=2的n次幂求an 在数列{an}中,a1=1,an+1=an^2,求an. 数列｛an｝满足a1=1,且an=an-1+3n-2,求an 数列{an}中,a1=1,an+1/an=n/n+2,求an