为什么lim n趋向于无穷大,（-2/5)^n=0

为什么lim n趋向于无穷大,（-2/5)^n=0 lim n趋向于无穷大n^5/e^n lim (1+1/2n)^n n趋向于无穷大 lim√1+1/n^2 n趋向于无穷大 lim(n趋向于无穷大 )(5n平方+n-2)/(3n平方-2) n趋向于无穷大,lim n[ln(n+2)-ln(n+1)], lim nsin(3x/n)=?n趋向于无穷大 证明lim(n/(n^2+1))=0(n趋向于无穷大） lim(n^2(cos1/n-1))(n趋向于无穷大） lim π^n/2^n+3^n.求极限lim n趋向于正无穷大.具体解算, lim π^n/(2^n+3^n).求极限lim n趋向于正无穷大.具体解算, 证明 lim(1-1/2^n)=1 n趋向于无穷大 lim(1-1/2^n)=1 n趋向于无穷大 求下列极限.lim(n趋向于无穷大)(2x次方)*(sin*1/2x次方) 用夹逼准则求lim(1/n^2+1/(n^2+1)+...+1/(2n)^2),n趋向于无穷大 lim(1/n+1/(n+1)^2+…+1/(2n)^2) n趋向于正无穷大 n趋向于无穷大时,极限LIM(n^2)sin^2(Θ/n)=-(Θ^2)/2 求具体过程. 极限lim n2^n/n^n= n趋向于无穷大极限lim n2^n/n^n=？