若x^2-y^2=24,x+y=6,求x+2y的值
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若x^2-y^2=24,x+y=6,求x+2y的值若x^2-y^2=24,x+y=6,求x+2y的值若x^2-y^2=24,x+y=6,求x+2y的值x²-y²=24,x+y=6x
若x^2-y^2=24,x+y=6,求x+2y的值
若x^2-y^2=24,x+y=6,求x+2y的值
若x^2-y^2=24,x+y=6,求x+2y的值
x²-y²=24,x+y=6
x²-y²=(x-y)(x+y)=24
∴x-y=4
x+y=6
解得:x=5
y=1
∴x+2y=5+1×2=7.
老师讲的,
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