log2 3×log3 7=log2 7这个算法对吗

log2 3×log3 7=log2 7这个算法对吗 log2^3*log3^7*log7^8 (log2 6)×(log3 6)-(log2 3+log3 2)= (log2 6)×(log3 6)-(log2 3+log3 2)= 设log3 7=a,log2 3=b,则log2 7=? log3(7)=a,log2(3)=b,则log2(7)=? 已知log3,7=a,log2,3=b,求log2,7的值.RT log3 7×log2 3=log2 7.这是为什么?对数解题有哪些要点? log2(3)*log3(2)=? (log3^2)(log2^3)= log2(3)+log3(5)+log3(2)=? log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙! 若log2(3)=a,log3(7)=b,用ab表示log2√21(3√7)拜托…! 高一数学代数求助 这个log2 7 怎样变成log3 7 × log2 3 比大小.log2 7 和log3 7 log3^7乘以log2^9乘以log49^2= log3^7乘以log2^9乘以log49^2= 为什么log3(2)=1/log2(3).