f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x+sin^4x)求最小正周期

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f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x+sin^4x)求最小正周期f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x

f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x+sin^4x)求最小正周期
f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x+sin^4x)求最小正周期

f(x)=√3(sin2x-cos2x)^2-cos(4x+π/3)+4(cos^4x+sin^4x)求最小正周期
详细答案见图片

是π/2