12x^2-10xy+2y^2+11x-5y+2 有谁告诉我可以怎么做啊~~~~~越快越好!
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/20 08:58:00
12x^2-10xy+2y^2+11x-5y+2有谁告诉我可以怎么做啊~~~~~越快越好!12x^2-10xy+2y^2+11x-5y+2有谁告诉我可以怎么做啊~~~~~越快越好!12x^2-10xy
12x^2-10xy+2y^2+11x-5y+2 有谁告诉我可以怎么做啊~~~~~越快越好!
12x^2-10xy+2y^2+11x-5y+2 有谁告诉我可以怎么做啊~~~~~
越快越好!
12x^2-10xy+2y^2+11x-5y+2 有谁告诉我可以怎么做啊~~~~~越快越好!
12x^2-10xy+2y^2+11x-5y+2干啥呢?
是不是因式分解?
若是,那么可以用待定系数法解
设12x^2-10xy+2y^2+11x-5y+2=(ax+by+c)(Ax+By+C)
这样,aA=12
bB=2
aB+bA=-10
aC+Ac=11
bC+cB=-5
Cc=2
因式分解:12xy^2(y-x)+xy^3(x-y)+4x^2y(x-y)
(x^2+xy/x-y)/(xy/x-y)计算
(-x-y)(x^2+xy+y^2)
化简x^-y^/x^-2xy+y^
2*(x-y)²(y-x)(xy)
x^2-xy/xy-y^2约分
.(x+y-2)(x+y-2xy)+(xy-1)^2
(x^2-xy)y÷y-x/xy怎么做?
求解12x²-10xy+2y²+11x-5y+2=0
代数 x^-y^/ x^-(y-z)^ 除以 x^+2xy+y^/(x-y)^-z^ 乘 x^+xy-xz/x^-xy
(x+y)/x /(x-(2xy-y^2)/x) 因式分解
(xy-x²)÷(x²-2xy+y²/xy)×(x-y/x²)
x-y/x²÷x²-2xy+y²/xy*(xy-x²)
已知xy-x-y=11,求(xy-1)^2+(x+y-2)(x+y-2xy)的值.
X-Y/2X+2Y XY/X+Y²
已知x-xy=10,xy-y=2,则x-y=( ),-2xy+x+y=( ).
已知x-xy =21,xy-y=-12,分别求式子x-y与x-2xy +y
已知x-xy=20,xy-y=12,则x-y= ,-2xy+x+y=