1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+2012)的值为多少
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1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+2012)的值为多少1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+
1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+2012)的值为多少
1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+2012)的值为多少
1/XY+1/(X+1)×(y+1)+1/(X+2)(y+2).1/(x+2012)(y+2012)的值为多少
x,y分别是什么呢?
这个要用到裂项法
裂项1/xy=(y-x)(1/x-1/y).加起来后中间抵消
最后结果1-1/2014
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xy-1+x-y
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(1)-3x²y+2x²y+3xy²-2xy²
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(xy+1)(x+1)(y+1)+xy
(xy+1)(x+1)(y+1)+xy