初一 数学 乘法公式 请详细解答,谢谢! (27 16:49:8)(m-n)(-m-n)=?(-m+11)(-m-11)=?(2+1)(2^2+1)(2^4+1)(2^8+1)+1
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初一 数学 乘法公式 请详细解答,谢谢! (27 16:49:8)(m-n)(-m-n)=?(-m+11)(-m-11)=?(2+1)(2^2+1)(2^4+1)(2^8+1)+1
初一 数学 乘法公式 请详细解答,谢谢! (27 16:49:8)
(m-n)(-m-n)=?
(-m+11)(-m-11)=?
(2+1)(2^2+1)(2^4+1)(2^8+1)+1
初一 数学 乘法公式 请详细解答,谢谢! (27 16:49:8)(m-n)(-m-n)=?(-m+11)(-m-11)=?(2+1)(2^2+1)(2^4+1)(2^8+1)+1
(m-n)(-m-n)=n^2-m^2
(-m+11)(-m-11)=m^2-121
(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)/(2-1)+1
=2^16-1+1
=2^16.
(m-n)(-m-n)=(-n)^2-m^2=n^2-m^2
(-m+11)(-m-11)=m^2-121
(2+1)(2^2+1)(2^4+1)(2^8+1)+1=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)+1=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1=(2^4-1)(2^4+1)(2^8+1)+1=(2^8-1)(2^8+1)+1=2^16-1+1=2^16
(m-n)(-m-n)=(m-n)[-(m+n)]=-(m^2-n^2)=n^2-m^2
(-m+11)(-m-11)=[-(m-11)][-(m+11)]=(m-11)(m+11)=m^2-121
(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^4-1)(2^4+1)(2^8+1)+1
=(2^8-1)(2^8+1)+1
=2^16-1+1
=2^16
够详细吧,祝学习进步!
(m-n)(-m-n)=-(m-n)(m+n)=-(mm-mn+mn-nn)=-(m^2-n^2)=n^2-m^2
(-m+11)(-m-11)=(m-11)(m+11)=m^2-11^2=m^2-121
(2+1)(2^2+1)(2^4+1)(2^8+1)+1=3*5*17*257+1=65536
(m-n)(-m-n)
=(n-m)(n+m)
=n^2-m^2
(-m+11)(-m-11)
=(m-11)(m+11)
=m^2-121
(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2-1)(2+1)(2^2+1)(2^4+1)(2^8+1)+1
=(2^2-1)(2^2+1)(2^4+1)(2^8+1)+1
=...
=(2^16-1)+1
=2^16