-sin a+μ cos a =0 怎么得出 a=arc tan μ

(cos a+sin a)/(cos a-sin a) 怎么算~ (sin a)/(1+cos a)=(1-cos a)/sin a怎么证sin a 1-cos a------ = -----------1+cos a sin a -sin a +μ cos a =0怎么得出 a=arc tan μ -sin a+μ cos a =0 怎么得出 a=arc tan μ 已知sin a-cos a=2sin a*cos a,则sin 2a的值怎么求? sin a + cos a = m .求 sin a -cos a (0度< a 已知sin a+cos a=m,求sin a-cos a(0 非线性方程解析解-x0*cos(b)*cos(c)-y0*(-sin(a)*cos(b)*cos(c)-cos(a)*sin(c))-z0*(-cos(a)*cos(b)*cos(c)+sin(a)*sin(c))=0-x0*cos(b)*sin(c)-y0*(-sin(a)*cos(b)*sin(c)+cos(a)*cos(c))-z0*(-cos(a)*cos(b)*sin(c)-sin(a)*cos(c))=0 -x0*cos(b)-y0*sin(a)*co sin a sin b +cos a cos b =0,则sin a cos a+sin b cos b的值 求非线性方程组的“解析解”-x0*cos(b)*cos(c)-y0*(-sin(a)*cos(b)*cos(c)-cos(a)*sin(c))-z0*(-cos(a)*cos(b)*cos(c)+sin(a)*sin(c))=0 -x0*cos(b)*sin(c)-y0*(-sin(a)*cos(b)*sin(c)+cos(a)*cos(c))-z0*(-cos(a)*cos(b)*sin(c)-sin(a)*cos(c))=0 -x0*cos =1-（sin^6a+cos^6a） ------（1）=1-（sin^a+cos^a)(sin^4 a-sin^acos6a+cos^4 a) --------（2）由（1）怎么能到（2）呢=1-（sin^6a+cos^6a）=1-（sin^2a+cos^2a)(sin^4 a-sin^2acos^2a+cos^4a) 求证1+sin a+cos a+2sin acos a/1+sin a+cos a=sin a+cos a 2*2矩阵（cos a,-sin a;sin a,cos a）^n=（cosn a,-sinn a;sinn a,cosn a）可以用欧拉公式证吗利用e^ina=cos na+i*sin na怎么证（cos a,-sin a;sin a,cos a）^n=（cos na,-sin na;sin na,cos na） sin平方A+cos平方A+sin A+cos A-1/sin平方A-cos平方A怎么计算 sin2A-sin2B=2cos(A+B)sin(A-B)=0那么2cos(A+B)sin(A-B)应该怎么算呢? sin(45+a)cos(45+a)怎么得=1/2sin(90+2a)? （高一）一道证明题,请问怎么证明?求证：（1 + sin a + cos a + 2 sin a cos a）/ （1 + sin a + cos a） = sin a + cos a 求证:sin 2a/1+sin a+cos a=sin a+cos a-1急