f(x)=1/(x-2),f(x)=1/3,求f[f(5)]
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f(x)=1/(x-2),f(x)=1/3,求f[f(5)]f(x)=1/(x-2),f(x)=1/3,求f[f(5)]f(x)=1/(x-2),f(x)=1/3,求f[f(5)]答:f(x)=1/(
f(x)=1/(x-2),f(x)=1/3,求f[f(5)]
f(x)=1/(x-2),f(x)=1/3,求f[f(5)]
f(x)=1/(x-2),f(x)=1/3,求f[f(5)]
答:
f(x)=1/(x-2)
f(5)=1/3
f [f(5)]=f(1/3)=1/(1/3-2)=1/(-5/3)=-3/5
所以:
f [f(5)]=-3/5
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