求∫1/(sin^4x+cos^4x)dx,

求∫1/(sin^4x+cos^4x)dx, d/dx sin^8(cos(4x)) 求微积分 ∫sin^2(x)cos^4(x) dx 求不定积分∫cos x/(sin x+cos x) d x, 求(1-sin^6x-cos^6x)/(1-sin^4x-cos^4x)的值 求1-cos^6x-sin^6x/1-cos^4x-sin^4x的值, ∫sin^3x/cos^4xdx 求积分, ∫sin^4xdx/cos^2x 求积分.坐等 ∫[1/(sin^2(x)cos^4(x)]dx 求解∫1/(cos^4(x)sin^2(x))dx 化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x 化简(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x) 求值：(1-sin^6 x-cos^6 x)/(1-sin^4 x-cos^4 x) 已知sin[a-b]cos a-cos[b-a]sin a=3/5,b是第三象限角,求sin[b+5π/4]的值第一题1/2cos x-√3/2sin x第二题√3sin x+cos x第三题√2[sin x-cos x]第四题√2cos x-√6sin x 化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2x 1/sin(x)+4/cos(x)=7*sin(x)cos(x) x为0到180度闭区间 求x sin^4x+cos^4x怎么求导数?