x+y+z=26 x-y=1 2x+z-y=18写好,按解方程组的格式
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x+y+z=26x-y=12x+z-y=18写好,按解方程组的格式x+y+z=26x-y=12x+z-y=18写好,按解方程组的格式x+y+z=26x-y=12x+z-y=18写好,按解方程组的格式x
x+y+z=26 x-y=1 2x+z-y=18写好,按解方程组的格式
x+y+z=26 x-y=1 2x+z-y=18
写好,按解方程组的格式
x+y+z=26 x-y=1 2x+z-y=18写好,按解方程组的格式
x+y+z=26 .① x-y=1.② 2x+z-y=18.③ 将②方程变换成X=1+Y 然后将①和③中的X用1+Y来代替 所以①就变成了1+Y+y+z=26 就是2y+z=25 ③就变成了2(1+Y)+z-y=18 就是z+y=16 最后用变换后的①-③就成了 y=9 然后再将y=9 代入变换后的②,所以X=10 最后将Y=9,X=10代进原来的① 就是9+10+Z=26 Z=7 所以 x=10 y=9 z=7
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(x+y-z)(x-y+z)=
X+y+z=26,x-y=1,2x-y+z=18
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
x+y+z=6 x+2y+3z=14 y+1=z
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
(x+y-z)^2-(x-y+z)^2=?
(x-y-z)*( )=x^2-(y+z)^2 填空
matlab解对数方程组[x,y,z]=solve('0.29744*x/(3+0.1*x+y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)))^2','0.79*x/(3+0.1*y+z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.1*y+z)))^2','1.25*x/(3+0.1*z)=(log10((3+x+y+z)/(3+0.1*x+y+z)*(3+y+z)/(3+0.*1y+z)*(3+z)/