cos(-5π/6)和cos(-3π/4)比较大小 详细过程谢谢
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cos(-5π/6)和cos(-3π/4)比较大小详细过程谢谢cos(-5π/6)和cos(-3π/4)比较大小详细过程谢谢cos(-5π/6)和cos(-3π/4)比较大小详细过程谢谢cos(-5π
cos(-5π/6)和cos(-3π/4)比较大小 详细过程谢谢
cos(-5π/6)和cos(-3π/4)比较大小 详细过程谢谢
cos(-5π/6)和cos(-3π/4)比较大小 详细过程谢谢
cos(-5π/6)=cos(5π/6)=cos(π-π/6)=-cosπ/6
cos(-3π/4)=cos(3π/4)=cos(π-π/4)=-cosπ/4
cosπ/6=1/2
cosπ/4=√2/2
cosπ/6-cosπ/4
即cos(-5π/6)>cos(-3π/4)
请及时点击右下角的【好评】按钮
计算:cos(π/5)+cos(2π/5)+cos(3π/5)+cos(4π/5)
cos(-5π/6)和cos(-3π/4)比较大小 详细过程谢谢
求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
求值:cos(π/11)-cos(2π/11)+cos(3π/11)-cos(4π/11)+cos(5π/11)
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)
Cos[π/7] + Cos[2 π/7] + Cos[3 π/7] + Cos[4 π/7] + Cos[5 π/7] + Cos[6 π/7] + Cos[7π/7]过程思路 不要只有答案哦
利用和差角公式化简 (2)sin(π/3+α)+sin(π/3-α)(2)sin(π/3+α)+sin(π/3-α)(3)cos(π/4+α)-cos(π/4-α)(4)cos(60°+α)+cos(60°-α)(5)sin(α-β)cosβ+cos(α-β)sinβ(6)cos(α+β)cosβ+sin(α+β)sinβ
求cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)求值:cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)(5/24)(11/24)=5/11?,而且过程和题好像都没关系。
cos(α+5π/12)cos(α+π/6)+cos(π/12-α)cos(π/3-α) 化简
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
利用诱导公式求三角函数值 cos 6/65π一,利用诱导公式:cos(2kπ+α)=cosα (k∈Z)和cos(π-α)=-cosα 得出cos65π/6=cos(65π/6-10π)=cos(5π/6)=cos(π-π/6)=-cosπ/6=-√3/2二,又或者cos65π/6=cos(11π-1π/6)=-cos(
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
cos(pai/15)×cos(2pai/15)×cos(3pai/15)×cos(4pai/15)×cos(5pai/15)×cos(6pai/15)×cos(7pai/15)求值
cos(π/11)cos(2π/11)cos(3π/11)cos(4π/11)cos(5π/11)怎么解
由cos(a+b)=cos a cos b-sin a sin b cos(a-b)=cos a cos b+sin a sin b解题设a为锐角,证:1、2分之根3乘cos a + 2分之1乘sin a=cos(6分之π-a)2、cos a-sin a=根号2cos(4分之π+a)
cos(2π/7)+cos(4π/7)+cos(6π/7)= -1/2.证明[cos(2π/7)]^2+[cos(4π/7)]^2+[cos(6π/7)]^2=5/4
cos(2π/7)+cos(4π/7)+cos(6π/7)= -1/2.证明[cos(2π/7)]^2+[cos(4π/7)]^2+[cos(6π/7)]^2=5/4
已知cosa=-4/5,a是第二象限角,求cos(a+π/3)和cos(a-π/3).