证明tan^2-sin^2=tan^2sin^2急用!
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 10:30:38
证明tan^2-sin^2=tan^2sin^2急用!证明tan^2-sin^2=tan^2sin^2急用!证明tan^2-sin^2=tan^2sin^2急用!tan^2-sin^2-tan^2si
证明tan^2-sin^2=tan^2sin^2急用!
证明tan^2-sin^2=tan^2sin^2
急用!
证明tan^2-sin^2=tan^2sin^2急用!
tan^2-sin^2-tan^2sin^2
=tan^2(1-sin^2) -sin^2
=tan^2cos^2-sin^2
=sin^2-sin^2
=0
所以tan^2-sin^2=tan^2sin^2
tan^2-sin^2= sin^2/ cos^2 - sin^2
=sin^2[(1/cos^2)-1]
=sin^2 * (1-cos^2)/cos^2
=tan^2sin^2
tan^2 - sin^2
= sin^2/cos^2 - sin^2
= (sin^2 - sin^2*cos^2) / (cos^2)
= sin^2(1 - cos^2) / (cos^2)
= sin^2(sin^2) / (cos^2)
= tan^2*sin^2
tan^2-sin^2=(sin^2-sin^2cos^2)/cos^2=sin^2(1-cos^2)/cos^2=sin^2*sin^2/cos^2=tan^2sin^2
证明:∵左边=tan^2-sin^2
= sin^2/cos2-sin^2
=sin^2(1/cos^2-1)
=sin^2(1/cos^2-cos^2/cos^2)
=sin^2(1-cos^2/cos^2)
=sin^2(sin^2/cos^2)
=sin^2tan^2
=右边
∴原式成立!
证明(tan^2-sin^2)cot^2=sin^2
证明 tanα=2tanβ
证明tan^2x-sin^2x=tan^2 sin^2x
证明:(tan^2)x-(sin^2)x=(tan^2)x(sin^2)x
证明:tan^2a-sin^2a=tan^2*sin^2a
证明:tan^2角-sin^2角=tan^2角sin^2角
证明tan^2-sin^2=tan^2sin^2急用!
数学证明sin^2 αtan^2 α=tan^2 α-sin^2 α
证明tanα/2=1-cosɑ/sinɑ
证明tan a/2=sin a/(1+cos a)
已知tan(a+b)=2tan a 证明 3sinb=sin(2a+b)
证明tan(x+y)+tan(x-y)=sin2x/cos^2x-sin^2y
sin(α+β)=1 证明tan(2α+β)+tanβ =0
证明:(1+tan a+cot a)/(1+tan^2 a+tan a)-cot a/(1+ tan^2 a)=sin a*cos a
(1+tanα+cotα)/(1+tan^2α+tanα)-cotα/(1+tan^2α)=sinα乘cosα麻烦帮忙证明下,
高1数学3角函数证明.tan^2-sin^2=tan^2·sin^2.题目就是这样tan平方减sin平方=tan平方乘sin平方,要证明,
证明tan^2x=2*tan^2y+1,求证sin^2y=2sin^2x-1
证明:1-2sinα cosα/cos^2α -sin^2α=1-tanα/1+tanα