若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
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若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=若tan(2x-y)=3tan(x-2y)=3,则tan(x+y
若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
tan(x+y)=tan[(2x-y)+(x-2y)]=[tan(2x-y)+tan(x-2y)]/[1-tan(x-2y)*tan(2x-y)]
=(3+1)/(1-3*1)=-2
由于tan(2x-y)=tan(x-2y),
因此
2x-y=x-2y+kπ,k为整数【因为tan函数周期为π】
x+y=kπ
tan(x+y)=tan(kπ)=0
若tan(2x-y)=3tan(x-2y)=3,则tan(x+y)=
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