若tan(3x+y)=2,tan(x+y)=-4 求tan2x
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若tan(3x+y)=2,tan(x+y)=-4求tan2x若tan(3x+y)=2,tan(x+y)=-4求tan2x若tan(3x+y)=2,tan(x+y)=-4求tan2x解tan2x=tan
若tan(3x+y)=2,tan(x+y)=-4 求tan2x
若tan(3x+y)=2,tan(x+y)=-4 求tan2x
若tan(3x+y)=2,tan(x+y)=-4 求tan2x
解
tan2x
=tan[(3x+y)-(x+y)]
=[tan(3x+y)-tan(x+y)]/[1+tan(3x+y)tan(x+y)]
=6/(1-8)
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若tan(3x+y)=2,tan(x+y)=-4 求tan2x
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