a-b=3-11a+11b

来源：学生作业帮助网编辑：六六作业网时间：2024/12/24 07:46:35

a-b=3-11a+11ba-b=3-11a+11ba-b=3-11a+11b解-11a+11b=-11*（a-b)=-11*3=-33-11a+11b=-11*（a-b)=-11*3=-33因为a-

a-b=3-11a+11b
a-b=3
-11a+11b

a-b=3-11a+11b
解 -11a+11b
= -11*（a-b)
= -11*3
=-33

-11a+11b
= -11*（a-b)
= -11*3
=-33

因为a-b=3.所以-11a+11b=-11(a-b)=-33

33 代入就可以了

a-b=3 -a+b=-3 两边同乘11 -11a+11b=-33 就采纳我的吧

这种题也来

-33

等于_33

已知A=5a-3b,B=-6a+4b,则A-B等于 A.-a+b,B=11a+b C.11a-7b D -a-7b 已知a=11,b=11分之一,求代数式a+2a+3a+...+9a+00a+10b+9b+...+3b+2b+b a-b=3-11a+11b 3a+b=50,a-3b=11,则(2a-b)^2-(a+2b)^2 如果(a+b)/(a-b)=11/3,那么(a*a)/(b*b)=?答案要准确,谢谢 (3a-4b)(7a-8b)+(11a-12b)(8b-7a) 如果a/b=11,a-b=3,a=( )b=( ）已知A+B=-3,A^+B^=-30,则A^-AB+B^+11=? 已知a+b=-3,a^b+ab^=-30,则a^-ab+b^+11 对自然数A,B,规定A@B=3A+2B-2求11@10 （3a+4b)(7a-8b)+(11a+2b)(8a-7a) 若7a-8b=5.求(3a-4b)(7a-8b)-(11a-12b)(8b-7a)的值 7a-8b=5,求(3a-4b)(7a-8b)-(11a-12b)(8b-7a) 化简a/b(a-b)-b/a(a-b)其中a=3 b=-2 已知a=11,b=1/11,代数式a+2a+3a+4a+.+9a+10a+10b+9b+8b+.+3b+2b+b的值是 (3a+2b)*(2a+b)*(a+b)= 两点A(a+2,b+2),B(b-a,-b)关于直线4x+3y=11对称,求a,b 已知a-b/a+b=-3,则代数式2(a-b)/a+b-5(a+b)/a-b=?