已知xx+x-1=0,求xxx+2xx的值
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已知xx+x-1=0,求xxx+2xx的值已知xx+x-1=0,求xxx+2xx的值已知xx+x-1=0,求xxx+2xx的值xx+x=1=>xxx+xx=x=>xxx+2xx=x+xx=1xx+x=
已知xx+x-1=0,求xxx+2xx的值
已知xx+x-1=0,求xxx+2xx的值
已知xx+x-1=0,求xxx+2xx的值
xx+x=1
=>
xxx+xx=x
=>
xxx+2xx=x+xx=1
xx+x=1
xxx+2xx=xxx+xx+xx=x(xx+x)+xx=x+xx=1
由XX+X-1=0知XXX+XX-X=0
两边均加XX得XXX+2XX-X=XX
所以XXX+2XX=XX+X=1
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