已知sin(360°+α)-cos(180°-α)=m则sin(180°+α)cos(180°-α)=?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/19 06:58:44
已知sin(360°+α)-cos(180°-α)=m则sin(180°+α)cos(180°-α)=?已知sin(360°+α)-cos(180°-α)=m则sin(180°+α)cos(180°-

已知sin(360°+α)-cos(180°-α)=m则sin(180°+α)cos(180°-α)=?
已知sin(360°+α)-cos(180°-α)=m
则sin(180°+α)cos(180°-α)=?

已知sin(360°+α)-cos(180°-α)=m则sin(180°+α)cos(180°-α)=?
sin(360°+α)-cos(180°-α)= sinα +cosα =m
(sinα +cosα)^2 = 1+2sinα*cosα =m^2,sinα*cosα=(m^2-1)/2
sin(180°+α)cos(180°-α)= -sinα(-cosα)=sinα*cosα=(m^2-1)/2