一道数学题50分.We want to mix two raw-materials (A,B) to make 1000 kg of a mixture with given chemical concentration.Material A contains 0% Cu and 10% Ni.Material B contains 1% Cu and 3% Ni.The mixture must contain at most 0.5% of Cu and betwee
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一道数学题50分.We want to mix two raw-materials (A,B) to make 1000 kg of a mixture with given chemical concentration.Material A contains 0% Cu and 10% Ni.Material B contains 1% Cu and 3% Ni.The mixture must contain at most 0.5% of Cu and betwee
一道数学题50分.
We want to mix two raw-materials (A,B) to make 1000 kg of a mixture with given chemical concentration.Material A contains 0% Cu and 10% Ni.Material B contains 1% Cu and 3% Ni.The mixture must contain at most 0.5% of Cu and between 6% and 7% of Ni.Raw material A costs 10 EUR/kg and B costs 12 EUR/kg.
a) Formulate the problem of finding the cheapest mixture as an LP problem.Decision variables xA and xB correspond to the amount of raw materials A and B in the mixture.
b) Transform the problem into the canonical form (equality constraints) by adding slack or surplus variables.
c) Form the Simplex table of the corresponding problem.You can do this either using pen and paper or in Excel.
给出答案和翻译的都将得到分的，我会在另外一个帖子给分。
一道数学题50分.We want to mix two raw-materials (A,B) to make 1000 kg of a mixture with given chemical concentration.Material A contains 0% Cu and 10% Ni.Material B contains 1% Cu and 3% Ni.The mixture must contain at most 0.5% of Cu and betwee
我们要组合两个原材料（甲,乙） ,使1000公斤的混合物与给定的化学浓度.材料A包含0 ％铜和10 ％倪.材料B含有百分之一铜和3 ％的镍.混合物必须含有最多的0.5 ％ ,铜和6 ％至7 ％的镍.原料A成本的10欧元/千克和B费12欧元/千克.
a ）制定的问题,找最便宜的混合物作为脂蛋白的问题.决策变量的XA和预算外对应金额的原材料A和B的混合物.
二）改造问题纳入范式（等式约束）加入呆滞或盈余变数.
c ）在表格单纯形表的相应问题.你可以这样做,无论是使用笔和纸,或在Excel .