若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,
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若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,若xy=1,x-2y=3,-6x^2y+12xy^2=多少?
若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,
若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,
若xy=1,x-2y=3,-6x^2y+12xy^2=多少?再加说明,
提出-6xy,原式=-6xy(x-2y)=-6*1*3=-18
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