tan(π/8)-cot(π/8)=?A.-2 B.-1 C.1 D.2
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/23 00:26:09
tan(π/8)-cot(π/8)=?A.-2B.-1C.1D.2tan(π/8)-cot(π/8)=?A.-2B.-1C.1D.2tan(π/8)-cot(π/8)=?A.-2B.-1C.1D.2t
tan(π/8)-cot(π/8)=?A.-2 B.-1 C.1 D.2
tan(π/8)-cot(π/8)=?
A.-2 B.-1 C.1 D.2
tan(π/8)-cot(π/8)=?A.-2 B.-1 C.1 D.2
tanπ/8-ctgπ/8
=(sinπ/8)/(cosπ/8)-(cosπ/8)/(sinπ/8)
=[(sinπ/8)^2-(cosπ/8)^2]/(sinπ/8*cosπ/8)
=(-cosπ/4)/[(1/2)*sinπ/4]
=-2
A.-2
化简tan(a)*cot(π-a)=
tan(π/8)-cot(π/8)=?A.-2 B.-1 C.1 D.2
tan(π/4-a)=cot(π/4+a)为什么
求tanπ/8 + cotπ/12的值(请写上cot的利用公式)
tan(π/8)-cot(π/8)的值为
sin(a-5π)/tan(3π-a)*cot(π/2-a)/tan(a-3π/2)*cos(8π-a)/sin(-a-4π)
tan(-a+3/2π)/cot(-a-π)化简
tan(π-a)=1/3,cot(3π-2a)=?
证明tan(π/4+a)-cot(π/4+a)=2tan2a
已知tan-1/1+tana=^2.求cot(a+4/π)RT
tan(3/2π-α)=?;cot(-α-π)=?
tanα=-cotθ θ属于(π/2,π)
cot(π/2+α)=tanα吗
tan(派/8)-cot(派/8)=?
化简:tan派/8+cot派/12=?
诱导公式推广tan(3/2π+α)=cotα还是tan(1/2π+α)=cotα
tan a+cot a=2,(tan a)的三次方+(cot a)的 三次方?
tan a+cot a=2,(tan a)的三次方+(cot a)的 三次方?