怎么化简cos(2x-π/3)-sin(2x-π/3),
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怎么化简cos(2x-π/3)-sin(2x-π/3),怎么化简cos(2x-π/3)-sin(2x-π/3),怎么化简cos(2x-π/3)-sin(2x-π/3),原式=√2sin(π/4-2x+
怎么化简cos(2x-π/3)-sin(2x-π/3),
怎么化简cos(2x-π/3)-sin(2x-π/3),
怎么化简cos(2x-π/3)-sin(2x-π/3),
原式=√2sin(π/4-2x+π/3)
=√2sin(7π/12-2x)
有什么不懂得追问
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