函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?

来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/26 13:51:23
函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?函数y=tan﹙π/2-x﹚,x∈﹙﹣π

函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?
函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?

函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?
x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚
π/2-x∈﹙π/4,π/2﹚∪﹙π/2,3π/4﹚
y=tan(π/2-x)的值域为(-无穷,-1)∪(1,+无穷)