己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/15 02:02:47
己知sin^2θ=sinαcosα求cos2θ=2sin(45°-α)cos(45°+α)急!~~己知sin^2θ=sinαcosα求cos2θ=2sin(45°-α)cos(45°+α)急!~~己知
己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
证明:
∵ 2sin(45°-α) cos(45°+α)
=2sin(45°-α) cos[90°-(45°-α)]
=2sin(45°-α) sin(45°-α)
=2sin²(45°-α)
=1-cos(90°-2α)
=1-sin2α
=1-2sinαcosα
=1-2sin²θ
=cos2θ
∴ cos2θ=2sin(45°-α) cos(45°+α)
己知sin^2θ=sinα cosα 求cos2θ=2sin(45°-α) cos(45°+α) 急!~~
己知tan=3.求sin-2cos分之3sin-cos
sinα=-2cosα,求sin^2α-3sinαcosα+1
己知sin^4θ+cos^4θ=5/9,求sin2θ的值
已知3sinα cosα=0,求 3cosα 5sinα/sinα-cosα与sin²α 2sinα
已知sinα=-3sinα.求①(sinα+2cos)/(2sinα-cosα).②(sinα^2)-(3cosα^2)+1
6sin^2α-sinαcosα-cos^2α=0,求cosα+sinα的值
已知sinα-2cosα=10求(sinα-4cosα)/(5sinα+2cosα)
已知sinα+3cosα=2,求(sinα-cosα)/(sinα+cosα)的值
已知sinα+3cosα=2,求(sinα-cosα)/(sinα+cosα)的值
sin(π-α)=-2sin(π/2+α),求sinα·cosα
已知sin(2α+β)-2sinαcos(α+β)=m,求sinβ
已知sinα+cosα/sinα-cosα=2,求3sinα+cosα/2sinα+3cosα的值
为什么2cosθ/2sinθ/2+2sinφ/2cosφ/2=sinα+sinβ
sinα+sinβ=1/3 求sinα-(cosβ)^2最大值
已知sinαsinβ=1/2,求cosαsinβ的范围.
已知(sinα+cosα)/(sinα-cosα)=2,求下列各式的值 (1)(3sinα+cos已知(sinα+cosα)/(sinα-cosα)=2,求下列各式的值(1)(3sinα+cosα)/(2sinα+3cosα)(2)sin²α-2sinαcosα+1
tanα=2,求3sinα+4cosα.2sinα-cosα