巳知x^2+y^2+4x+6y+13=0,且x、y为实数.则xy^2=?

已知x^2+y^2+13-4x+6y=0,求(2x-y)^2-2(2x-y)(x+2y)+(x+2y)^2 化简求值：已知x、y满足：x^2+y^2-4x+6y+13=0 求代数式 的值.(3x+y)^2-3(3x-y)(x+y)-(x-3y)(x+3y)急用！ x^2+y^2+6x-4y+13=0求x,y,x^2-y^2的值 如果有理数x.y满足x^2+y^2+4x-6y+13=0,则y^x=? x平方-4x+2y+6y+13=0则x= y=? 已知：x^2+y^2+4x-6y+13=0,求x^y值. x^2+y^2+4x-6y+13=0,求x^y的值 x^2+y^2-4x+6y+13=0,x,y的值 x^2-4x+y^2-6y+13=0求x,y的值 若x^2+y^2-6x+4y+13=0 求x+y 因式分解 若 x^2+4x+y^2-6y+13=0 求y^x 已知x²+y²-6x+4y+13=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)²已知x²+y²-6x+4y+13=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)² 已知x、y满足x2+y2-4x+6y+13=0 求代数式（3x+y)2-3(3x-y)(x+y)-(x-3y)(x+3y)已知x、y满足x^2+y^2-4x+6y+13=0 求代数式（3x+y)^2-3(3x-y)(x+y)-(x-3y)(x+3y)的值 已知X^2+Y^2+4X-6Y+13=0,X、Y为实数,则Y^2等于? 已知x.x+y.y+8x+6y+25=0,求代数式(x.x-4y.y)/(x.x+4xy+4y.y)-x/(x+2y)的值 （x+y）/2- x-y/2=6 3(x+y)=4(x-y) x+y/3+x-y/2=6 4(x+y)-2(x-y)=40 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1