x^3+y^2-5=7,则2x^3+2y^2+4=?
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x^3+y^2-5=7,则2x^3+2y^2+4=?x^3+y^2-5=7,则2x^3+2y^2+4=?x^3+y^2-5=7,则2x^3+2y^2+4=?解;因为x³+y²-5=
x^3+y^2-5=7,则2x^3+2y^2+4=?
x^3+y^2-5=7,则2x^3+2y^2+4=?
x^3+y^2-5=7,则2x^3+2y^2+4=?
解;因为x³+y²-5=7
所以x³+y²=12
所以2x³+2y²=24
所以2x^3+2y^2+4=28
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