{2x-y+3z=14 x-y+z=4 3x-y-z=2
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{2x-y+3z=14x-y+z=43x-y-z=2{2x-y+3z=14x-y+z=43x-y-z=2{2x-y+3z=14x-y+z=43x-y-z=22x-y+3z=14——①x-y+z=4——
{2x-y+3z=14 x-y+z=4 3x-y-z=2
{2x-y+3z=14 x-y+z=4 3x-y-z=2
{2x-y+3z=14 x-y+z=4 3x-y-z=2
2x-y+3z=14 ——①
x-y+z=4 ——②
3x-y-z=2——③
②×2:2x-2y+2z=8——④
①-②:y+z=6——⑤
①+②:3x-2y+4z=18——⑥
③-⑥:y-5z=-16——⑦
⑤-⑦:6z=22
z=22/3
代入⑤得:y=-4/3
代入②得:x=-14/3
x+y/2=z+x/3=y+z/4 x+y+z=27
x+2y=3x+2z=4y+z 求x:y:z
x+y+z=6 x+2y+3z=14 y+1=z
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
2x+y+3z=14 x-y+z=4 3x-y-z=2
{2x-y+3z=14 x-y+z=4 3x-y-z=2
已知2x+5y+4z=15.7x+y+3z=14 则x+y+z=?
2x+z=10 x+y-z=4 3x-y-z=0
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
三元一次方程组,1.x-2y+z=9 2x+y+3z=10 3x+2y1.x-2y+z=92x+y+3z=103x+2y-z2.3x-5y+2z=14x+5y-z=5X-5y+3z=-23.7x+2y-z=76x-y+z=74x+3y+z=94.4x+3y-2z=-75x-6y+z=12x+z=-25.2x+3y-4z=-23x-2y+5z=262x+5z=31
(4x-2y-z)-{5x-[8y-2z-(x-2y)]-x-(3y-10z)}=?
3x-y+z=4,2z+3y-z=12,x+y+z=6的解
x/2=y/3=z/4,则x+2y-z/z=?
证明 :x/(y+z)+y/(z+x)+z/(x+y)>=3/2其中 x,y,z>0
设|x|-|y|+|z|=|x+y+z|,且|x+y|=4,|y+z|=5,|y|=3,求(x-y-z)^2的值
x+y+z=14 7z=x+y+2 x+z=y
14x+4y+z=200,x+y+z=100求解x,y,z