若函数f(x)=asin(π+a)+bcos(π+β),且f(1999)=-1,则f(2010)=?

若函数f(x)=Asin(wx+a)(w>0,A>0,x属于R,-π 已知函数f(x)=Asin(2x+a),若函数f(x+π/6)为偶函数,且f(π/6)=4,求f(x)解析式 若函数f(x)=asin(π+a)+bcos(π+β),且f(1999)=-1,则f(2010)=? 已知函数f(x)=Asin(x+&)(A>0,0 设函数f(x)=asin(x)+b (a 函数f(x)=Asin(wx+φ),A>0,|φ| 已知函数 f(x)=Asin(π/3x+b),x∈R,A>0,0 已知函数f(x)=Asin(ωx+a)(A>0,ω>0,-π/2 已知函数f(x)=更号2asin(x-π/4)+a+b 当a 函数f(x)=Asin(ωx+φ)(A＞0 ω＞0 -π/2 已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,-π/2 已知函数f(x)=Asin(ωx+ψ)(A.>0,w>0,-π 已知函数f(x)=Asin(ωx+φ)(A>0,ω>0,-π 若函数f(x)=Asin(ωx+ψ)(A>0,ω>0,0 若函数f(x)=Asin(x+φ)(A>0,|φ| 已知函数f(x)=Asin(wx+a)(A>0,w>0,-π/2 已知函数f(x)=Asin(wx+φ)(其中A>0,w>0,-π/2 已知函数f(x)=Asin(wx+α)(A>0,w>0,-π/2