X2y2-x2-y2+1因式分解.
来源：学生作业帮助网 编辑：六六作业网 时间：2024/11/08 09:39:23
X2y2-x2-y2+1因式分解.X2y2-x2-y2+1因式分解.X2y2-x2-y2+1因式分解.x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1)=(x+1)(x-1)(y+1)
X2y2-x2-y2+1因式分解.
X2y2-x2-y2+1因式分解.
X2y2-x2-y2+1因式分解.
x^2(y^2-1)-(y^2-1)=(x^2-1)(y^2-1)=(x+1)(x-1)(y+1)(y-1)
x^2y^2-x^2-y^2+1
=x^2(y^2-1)-(y^2-1)
=(x^2-1)(y^2-1)
X2y2-x2-y2+1
=x2(y2-1)-(y2-1)
=(y2-1)(x2-1)
=(y+1)(y-1)(x+1)(x-1)
x^2y^2-x^2-y^2+1
=x^2(y^2-1)-(y^2-1)
=(x^2-1)(y^2-1)
因式分解x2y2-x2-y2+1
X2y2-x2-y2+1因式分解.
(x2+y2-1)-4x2y2因式分解2是平方
(x2+y2)2-4x2y2 因式分解
因式分解(x2+y2-a2)2-4x2y2
(x2+y2)(x2-xy+y2)-2x2y2因式分解
因式分解x2＋y2－x2y2－4xy－1；
x2+y2-x2y2-4xy-1
因式分解：（1）36-x2 （2）-a2+b2 （3）x2-16y2 （4）x2y2-z2
x2y2-x2-y2+4xy+1分解因式
因式分解,x4-7x2y2+y4=?x4-7x2y2+y4=?应该是(x2+?xy+y2)(x2-?xy+y2) 的形式,那个?是多少
x4－2x2y2－3x2＋6y2因式分解
因式分解（z2-x2-y2）2-4x2y2,用初二知识解答
(z2-x2-y2)2-4x2y2=?因式分解,题中的“2”均为平方,无乘号.
因式分解 x5n+xn+1 2a2-a2b+(b-2)(ab-a)2 x5+x4+x3+x2+x+1 x4+y4-2x2y2-2x2-2y2+1
求极限lim(x,y)→(0,0) [1-cos(x2+y2)]/[(x2+y2)e^x2y2]
4x4y4-5x2y2-9y2因式分解
4x2y2-(x2+y2)2的答案