设y=e负X的次方cos(3-x)则dy=
来源:学生作业帮助网 编辑:六六作业网 时间:2024/11/13 04:34:53
设y=e负X的次方cos(3-x)则dy=设y=e负X的次方cos(3-x)则dy=设y=e负X的次方cos(3-x)则dy=[-(e-x次方)cos(3-x)+(e-x次方)sin(3-x)]dy
设y=e负X的次方cos(3-x)则dy=
设y=e负X的次方cos(3-x)则dy=
设y=e负X的次方cos(3-x)则dy=
[-(e-x次方)cos(3-x)+(e-x次方)sin(3-x)]dy
设y=e负X的次方cos(3-x)则dy=
设y=cos根号下x,减去e的负2x方,求dy
设y=3的x次方+e的3次方,则dy=( )
设Y=cos根号X-e负X平方 ,求 DY
设Y=e的X次方-lncosx 求dy
设y=e(-1/x)次方,则dy=
设y=e^(-x) cos 1/x,求dy.
设y=cos(x^2+e^x)求dy
设y=e^cos^2*1/x,求dy
设y=e^cos^21/x,求dy
设e^(x+y)+cos(xy)=0确定y是x的函数求dy
设x=a cos的3次方t y=a sin的3次方t求dy/dx
设(x+y)的平方=e的(x-y)次方,求dy/dx,
设y=e^(-x)cos(3-x),求dy 详细些
COS(x+y)+e的y次方=1 求 dy
微积分设y=x的5次方+e的sinx次方 求dy
设y=x的5次方+e的sinx次方,求dy怎么解?
求 微分方程(x+1)dy/dx+1=e的负y次方 的通解