1元2次方程求解:100x-100=9x^2

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1元2次方程求解:100x-100=9x^21元2次方程求解:100x-100=9x^21元2次方程求解:100x-100=9x^2用因式分解法:9x^2-100x+100=0即(x-10)(9x-1

1元2次方程求解:100x-100=9x^2
1元2次方程求解:
100x-100=9x^2

1元2次方程求解:100x-100=9x^2
用因式分解法:
9x^2-100x+100=0
即(x-10)(9x-10)=0
x1=10,x2=10/9

20或 10/9

原式可化为
9x^2-100x+100=0;

(9x-10)*(x-10)=0;
解得
x1=10/9;x2=10.