证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx(0,π)中,0是下限,π是上限,后面同理,求详解
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证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx(0,π)中,0是下限,π是上限,后面同理,求详解证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx(0,
证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx(0,π)中,0是下限,π是上限,后面同理,求详解
证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx
(0,π)中,0是下限,π是上限,后面同理,求详解
证明∫(0,π)f(sinx)dx=2∫(0,π/2)f(sinx)dx(0,π)中,0是下限,π是上限,后面同理,求详解
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