(2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)

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(2)(x-2)(x+2)-(x+1)(x-3)(3)(ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)(2)(x-2)(x+2)-(x+1)(

(2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)
(2)(x-2)(x+2)-(x+1)(x-3)
(3) (ab+1)²-(ab-1)²
(4)(2x-y)²-4(x-y)(x+2y)

(2)(x-2)(x+2)-(x+1)(x-3)(3) (ab+1)²-(ab-1)²(4)(2x-y)²-4(x-y)(x+2y)
(2)(x-2)(x+2)-(x+1)(x-3)
=x²-4-(x²-2x-3)
=x²-4-x²+2x+3
=2x-1
(3) (ab+1)²-(ab-1)²
=(ab+1+ab-1)(ab+1-ab+1)
=2(2ab)
=4ab
(4)(2x-y)²-4(x-y)(x+2y)
=4x²-4xy+y²-4(x²+xy-2y²)
=4x²-4xy+y²-4x²-4xy+8y²
=-8xy+9y²

这个不是初一的吧,分解因式,初二的

化简?

很简单的题你都不会做?我也是初一的。。。呵呵