x-y=1 x+z=2 z-y=17x-y=1(1)x+z=2(2) z-y=17(3)
来源:学生作业帮助网 编辑:六六作业网 时间:2024/12/26 21:46:22
x-y=1x+z=2z-y=17x-y=1(1)x+z=2(2)z-y=17(3)x-y=1x+z=2z-y=17x-y=1(1)x+z=2(2)z-y=17(3)x-y=1x+z=2z-y=17x-
x-y=1 x+z=2 z-y=17x-y=1(1)x+z=2(2) z-y=17(3)
x-y=1 x+z=2 z-y=17
x-y=1(1)
x+z=2(2)
z-y=17(3)
x-y=1 x+z=2 z-y=17x-y=1(1)x+z=2(2) z-y=17(3)
(1)+(3)得 x+z-2y=18(4) 因为 x+z=2(2) 所以 2y =-16 y=-8
将y=-8带入(1) (3)可得x= -7 z=9
汗水,小学生要好好学习,不要总问答案
-7 -8 9
X=-7
y=-8
Z=9
(1)-(3) 求出X-Z=-16 (4) 然后(4)+(2)得2X=-14 所以X=-7 Z=9 Y=-8
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
(x+y-z)(x-y+z)=
用行列式的性质证明:y+z z+x x+y x y z x+y y+z z+x =2 z x y z+x x+y y+z y z x 这个怎么证?
(x-2y+z)(x+y-2z)分之(y-x)(z-x) + (x+y-2z)(y+z-2x)分之(z-y)(x-y) + (y+z-2z)(x-2y+z)分之(x-z)(y-z)=?第三部分那个是 (y+z-2x)(x-2y+z)分之(x-z)(y-z)
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值
X+Y+Z=?
x/y=(x+z)/(y+z)y/z=(x+y)/(x+z)
方程组:{x+y-z=6,x+z=16,x-y+2z=17
x+y+z=6 x+2y+3z=14 y+1=z
若|x+3|+|y-2|+|2×z+1|=0求(x×z-y×z)(y-x+z)的值
x-y=1 x+z=2 z-y=17x-y=1(1)x+z=2(2) z-y=17(3)
(y+z)/x=(z+x)/y=(x+y)/z求x+y-z/x+y+z的值
(x+y-z)^2-(x-y+z)^2=?