x+1分之x的2次方-x+1

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x+1分之x的2次方-x+1x+1分之x的2次方-x+1x+1分之x的2次方-x+1原式=x²/(x+1)-(x-1)=[x²-(x+1)(x-1)]/(x+1)=(x²

x+1分之x的2次方-x+1
x+1分之x的2次方-x+1

x+1分之x的2次方-x+1
原式=x²/(x+1)-(x-1)
=[x²-(x+1)(x-1)]/(x+1)
=(x²-x²+1)/(x+1)
=1/(x+)