若lg[log2(log1/3 x)]=0,则x^-1/4=

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若lg[log2(log1/3x)]=0,则x^-1/4=若lg[log2(log1/3x)]=0,则x^-1/4=若lg[log2(log1/3x)]=0,则x^-1/4=根据题意有:log2(lo

若lg[log2(log1/3 x)]=0,则x^-1/4=
若lg[log2(log1/3 x)]=0,则x^-1/4=

若lg[log2(log1/3 x)]=0,则x^-1/4=
根据题意有:
log2(log1/3 x)=1
进一步:
log(1/3)x=2
所以:
x=(1/3)^2=1/9.
x^(-1/4)
=(1/9)^(-1/4)
=9^(1/4)
=√3.