2log2（12）怎么转化成log2（3）?

2log2（12）怎么转化成log2（3）? log2（√1/48）+log2 12-1/2log2 （24）-1/3 如何把2log2 7转化为 2（log2 14）-log2 2 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? 计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9 [log2(3)]^2怎么算? 求值：log2 (5/56)^(1/2)+log2 (14)-(1/2)log2 (35)=log2中2为底数=1/2[-2log2 (7)-3]+log2 (2)+log2 (7) 中的1/2[-2log2 (7)-3]是怎么得到的？ (log2 x)=(log2 x)^2-log2 x+2 (1) =(log2 x-0.5)^2+7/4 (2) 第一步式子 如何转化成第二步的 化简算式log2^√7/48+log2^12-1/2log2^42+1/2^log2^3 =[1/(log2 3)+lg2 3]²-[1/(log2 3)]²-(log2 3)²=2*(1/log2 3)*log2 3,怎么转的啊 log2(3),log2(3^x-1),log2（3^x+37/3）成等差数列,求x 计算：log2(18)-2log2（6）+2^【3-log2(3)】 log2 SQR(7/48)+log2 12 -1/2log2 42 log2 SQR(7/48)+log2 12 -1/2log2 48 (log2 9)/(log2 8) = 2/3(log2 3) log2 3乘以log2 3等于2log2 log2^(4^7*2^5)+log2^6-log2^3 |[log2(x)]^2-3log2(x)+1|