sin(π/4-x)=5/13,则sin2x=?
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sin(π/4-x)=5/13,则sin2x=?sin(π/4-x)=5/13,则sin2x=?sin(π/4-x)=5/13,则sin2x=?sin2x=cos(π/2-2x)=cos2(π/4-x
sin(π/4-x)=5/13,则sin2x=?
sin(π/4-x)=5/13,则sin2x=?
sin(π/4-x)=5/13,则sin2x=?
sin2x
=cos(π/2-2x)
=cos2(π/4-x)
=1-2[sin(π/4-x)]^2 (余弦2倍角公式)
=1-2(5/13)^2
=119/169.
sin(π/4-x)=5/13,则sin2x=?
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