已知sin(x+π/4)=3/5,sin(x-π/4)=4/5 ,则tanx=
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已知sin(x+π/4)=3/5,sin(x-π/4)=4/5,则tanx=已知sin(x+π/4)=3/5,sin(x-π/4)=4/5,则tanx=已知sin(x+π/4)=3/5,sin(x-π
已知sin(x+π/4)=3/5,sin(x-π/4)=4/5 ,则tanx=
已知sin(x+π/4)=3/5,sin(x-π/4)=4/5 ,则tanx=
已知sin(x+π/4)=3/5,sin(x-π/4)=4/5 ,则tanx=
答:
sin(x+π/4)=3/5
sin(x-π/4)=4/5
两式相加得:
2sinxcos(π/4)=7/5
同理,两式相减得:
2cosxsin(π/4)=-1/5
上两式相除得:
tanx=-7
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