x-4/(x-1)(x+1)=A/X-1+B/X+1
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x-4/(x-1)(x+1)=A/X-1+B/X+1x-4/(x-1)(x+1)=A/X-1+B/X+1x-4/(x-1)(x+1)=A/X-1+B/X+1(x-4)/(x-1)(x+1)=A/(X-
x-4/(x-1)(x+1)=A/X-1+B/X+1
x-4/(x-1)(x+1)=A/X-1+B/X+1
x-4/(x-1)(x+1)=A/X-1+B/X+1
(x-4)/(x-1)(x+1)=A/(X-1)+B/(X+1)=[(A+B)x+(A-B)]/(x-1)(x+1)
A+B=1,A-B=-4,A=-1.5,B=2.5
a+x/x+1 ,x/x^2-2x-3 ,a/x^2+4x+3
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
设函数f(x)={a/x+b/(x²-x) x>1{x x
1、A={x||x|
A={x||x-1|
A={x| |x-1|
已知集合A={x|(x-2)*(x+1)>0},B={x|4x+a
若f(x)={a'x(x>1),(4-a/2)x+2(x
f(x)=(3a-1)x+4a,x
f(x)=(3a-1)x+4a,x
f(x)=(3a-1)x+4a,x
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
如何用C语言编写方程:A*x*x*x*x*x*x+B*x*x*x+C*x*x+D*x+E*(1+F*x*x)*x*x*exp(-G*x*x)-H=0
x-4/(x-1)(x+1)=A/X-1+B/X+1
X(X-1)=X
设集合A={x|x>3},B={x| x-1/x-4
4x+1/(x-2)(x-5)=a/x-2+b/x-5
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做