若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)²的值

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若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)²的值若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)&#

若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)²的值
若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)²的值

若a+19=b+9=c+11,求(a-b)²-(b-c)²+(a-c)²的值
a+19=b+9=c+11
则:
a-b=9-19=-10
b-c=11-9=2
a-c=11-19=-8
(a-b)²-(b-c)²+(a-c)²
=10²-2²+8²
=100-4+64
=162

a-b=-10;b-c=2;a-c=-8;(a-b)²-(b-c)²+(a-c)²=100-4+64=160