如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EAC.求证:AM=AN
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如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EAC.求证:AM=AN如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EA
如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EAC.求证:AM=AN
如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EAC.求证:AM=AN
如图,AB=AC,AD=AE,AB,DC相交于点M,AC,BE相交于点N,角DAB=角EAC.求证:AM=AN
证明:∵角DAB=角EAC
∴角DAC=∠EAB,又AB=AC,AD=AE
∴△ADC≌△AEB
∴∠B=∠C
又AB=AC,∠MAN为公共角
∴△AMC≌△ANB
∴AM=AN
在△DAM与△EAN中
{AB=AC
AD=AE
角DAB=角EAC
所以△DAM全等于△EAN
所以AM=AN
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