(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
来源：学生作业帮助网 编辑：六六作业网 时间：2025/01/23 07:53:24
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)4x^n-2x^n-
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
4x^n-2x^n-1-3x^n+2=x^(n-1)[4x-2-3x^2] 同时提取x^(n-1)
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)=x^(n-1)[3x^2-4x+2]/x^(n-1)[5x]=
=(3x^2-4x+2)/(5x)
(4x^n-2x^n-1-3x^n+2)÷（-5x^n-1)
x^n-1(3x^n+4x^n+1-5x^n+2)
x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
x^(n)*x^(n+1)+x^(2n)*x
(-x)^3x^n-1+x^2n(-x)^3
因式分解：x^(2n)+(2x)^(n)+4^(n-1)
x^2n+(2x)^n+4^(n-1) 因式分解
若(x^2+1/x)^n(n∈N+,n
(8x^n+1-3x^n-1)-2(-x+9x^n+1-4x^n)=
计算(x^(2n)+x^n+1)(x^(3n)-x^(2n)+1)
因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)
因式分解4x^n+2-9x^n+6x^n-1-x^n-2
因式分解：(x^n+1)+(2x^n)+(x^n-1)
x^n+1-2x^n+x^n-1因式分解
x^n-1-2x^n+x^n-1因式分解
(x^4n/x^2n)*x^n
分解因式x^n-x^(n-1)+x^(n-2)